A. W - 2P cosθ
B. W - P cosθ
C. W - P sinθ
D. W - 2P sinθ
Answer: Option D
This Question Belongs to Civil Engineering >> RCC Structures Design
Distribution of shear intensity over a rectangular section of a beam, follows:
A. A circular curve
B. A straight line
C. A parabolic curve
D. An elliptical curve
If the shear stress in a R.C.C. beam is
A. Equal or less than 5 kg/cm2, no shear reinforcement is provided
B. Greater than 4 kg/cm2, but less than 20 kg/cm2, shear reinforcement is provided
C. Greater than 20 kg/cm2, the size of the section is changed
D. All the above
In a pre-stressed member it is advisable to use
A. Low strength concrete only
B. High strength concrete only
C. Low strength concrete but high tensile steel
D. High strength concrete and high tensile steel
In a simply supported slab, alternate bars are curtailed at
A. $${\frac{1}{4}^{{\text{th}}}}$$ of the span
B. $${\frac{1}{5}^{{\text{th}}}}$$ of the span
C. $${\frac{1}{6}^{{\text{th}}}}$$ of the span
D. $${\frac{1}{7}^{{\text{th}}}}$$ of the span
The net downward load at the center of the beam is:
W - 2P sin(α)
This is because the pre-stressed load P is acting in the opposite direction to the external load W, and the angle of inclination α affects the vertical component of the pre-stressed load.
Here's the breakdown:
- W is the external load acting downward
- 2P sin(α) is the upward component of the pre-stressed load, where:
- 2P is the total pre-stressed load (acting in both directions)
- sin(α) is the vertical component of the pre-stressed load, due to the angle of inclination α
So, the net downward load at the center is the external load minus the upward component of the pre-stressed load.