# In a pre-stressed beam carrying an external load W with a bent tendon is having angle of inclination θ and pre-stressed load P. The net downward load at the centre is

A. W - 2P cosθ

B. W - P cosθ

C. W - P sinθ

D. W - 2P sinθ

**Answer: Option D **

A. W - 2P cosθ

B. W - P cosθ

C. W - P sinθ

D. W - 2P sinθ

**Answer: Option D **

Related Questions on RCC Structures Design

**Distribution of shear intensity over a rectangular section of a beam, follows:**

A. A circular curve

B. A straight line

C. A parabolic curve

D. An elliptical curve

**If the shear stress in a R.C.C. beam is**

A. Equal or less than 5 kg/cm^{2}, no shear reinforcement is provided

B. Greater than 4 kg/cm^{2}, but less than 20 kg/cm^{2}, shear reinforcement is provided

C. Greater than 20 kg/cm^{2}, the size of the section is changed

D. All the above

**In a pre-stressed member it is advisable to use**

A. Low strength concrete only

B. High strength concrete only

C. Low strength concrete but high tensile steel

D. High strength concrete and high tensile steel

**In a simply supported slab, alternate bars are curtailed at**

A. $${\frac{1}{4}^{{\text{th}}}}$$ of the span

B. $${\frac{1}{5}^{{\text{th}}}}$$ of the span

C. $${\frac{1}{6}^{{\text{th}}}}$$ of the span

D. $${\frac{1}{7}^{{\text{th}}}}$$ of the span

The net downward load at the center of the beam is:

W - 2P sin(α)

This is because the pre-stressed load P is acting in the opposite direction to the external load W, and the angle of inclination α affects the vertical component of the pre-stressed load.

Here's the breakdown:

- W is the external load acting downward

- 2P sin(α) is the upward component of the pre-stressed load, where:

- 2P is the total pre-stressed load (acting in both directions)

- sin(α) is the vertical component of the pre-stressed load, due to the angle of inclination α

So, the net downward load at the center is the external load minus the upward component of the pre-stressed load.