In a race where 12 cars are running, the chance that car X will win is $$\frac{1}{6},$$ that Y will win is $$\frac{{1}}{{10}}$$ and that Z will win is $$\frac{{1}}{{8}}$$. Assuming that a dead heat is impossible. Find the chance that one of them will win.
A. $$\frac{{47}}{{120}}$$
B. $$\frac{{1}}{{480}}$$
C. $$\frac{{1}}{{160}}$$
D. $$\frac{{1}}{{240}}$$
Answer: Option A
Solution(By Examveda Team)
Required probability = P(X) + P(Y) + P(Z) (all the events are mutually exclusive)$$\eqalign{ & = \frac{1}{6} + \frac{1}{{10}} + \frac{1}{8} \cr & = \frac{{47}}{{120}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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