In a set of 30 game cards, 17 are white and rest are green. 4 white and 5 green are marked IMPORTANT. If a card is chosen randomly from this set, what is the possibility of choosing a green card or an ‘IMPORTANT’ card?
A. $$\frac{{13}}{{30}}$$
B. $$\frac{{22}}{{30}}$$
C. $$\frac{{17}}{{30}}$$
D. $$\frac{{9}}{{13}}$$
Answer: Option C
Solution(By Examveda Team)
We want green card or IMPORTANT cardThere are 30 - 17 = 13 green cards
There are 4 + 5 = 9 IMPORTANT cards
Total cards = 30
Also 5 green cards are IMPORTANT cards
So probability
$$\eqalign{ & = \frac{{13}}{{30}} + \frac{9}{{30}} - \frac{5}{{30}} \cr & = \frac{{17}}{{30}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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