In a simultaneous throw of two dice, what is the probability of getting a doublet ?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{4}}$$
C. $$\frac{{2}}{{3}}$$
D. $$\frac{{3}}{{7}}$$
Answer: Option A
Solution(By Examveda Team)
In a simultaneous throw of dice, n (S) = (6 × 6) = 36Let E = event of getting a doublet
= [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)]
∴ P(E) = $$\frac{{n (E)}}{{n (S)}}$$ = $$\frac{{6}}{{36}}$$ = $$\frac{{1}}{{6}}$$
This Question Belongs to Arithmetic Ability >> Probability
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