In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?
A. $$\frac{1}{4}$$
B. $$\frac{1}{6}$$
C. $$\frac{7}{12}$$
D. $$\frac{5}{36}$$
Answer: Option D
Solution(By Examveda Team)
In a simultaneous throw of two dice, we have n (S) = (6 × 6) = 36Let E = event of getting a total of 10 or 11
= [(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)]
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{5}{{36}}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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