In a simultaneous throw of two dice, what is the probability of getting a total of 7?
A. $$\frac{1}{6}$$
B. $$\frac{1}{4}$$
C. $$\frac{2}{3}$$
D. $$\frac{3}{4}$$
Answer: Option A
Solution(By Examveda Team)
We know that in a simultaneous throw of two dice,n(S) = 6 × 6 = 36
Let E = event of getting a total of 7
= {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{6}{{36}} = \frac{1}{6}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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