In a single throw of die, what is the probability of getting a number greater than 4 ?

A. $$\frac{1}{2}$$

B. $$\frac{1}{3}$$

C. $$\frac{2}{3}$$

D. $$\frac{1}{4}$$

Answer: Option B

Solution(By Examveda Team)

When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{6} = \frac{1}{3}$$