?
In a single throw of die, what is the probability of getting a number greater than 4 ?
Answer & Solution
Correct Answer:
Option
B
When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{6} = \frac{1}{3}$$
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{6} = \frac{1}{3}$$
Join the Discussion
Login to post a comment or share your explanation.
Login