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In an examination A got 25% marks more than B, B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, the marks obtained by A were :

A. 405

B. 450

C. 360

D. 400

Answer: Option B

Solution(By Examveda Team)

Marks obtained by D = 320
Marks obtained by C
= 320 × $$\frac{125}{100}$$ = 400
Marks obtained by B
= 400 × $$\frac{(100 - 10)}{100}$$   = 360
Marks obtained by A
= 360 × $$\frac{125}{100}$$ = 450
Hence, required marks obtained by A = 450

This Question Belongs to Arithmetic Ability >> Percentage

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