In an examination, B obtained 20%, more marks than those obtained by A, and A obtained 10% less marks than those obtained by C. D obtained 20% marks than those obtained by C. By what percentage are the marks obtained by D more than those obtained by A?
A. $$43\frac{1}{3}\% $$
B. $$23\frac{1}{3}\% $$
C. $$13\frac{1}{3}\% $$
D. $$33\frac{1}{3}\% $$
Answer: Option D
Solution (By Examveda Team)
Let C marks = 100
More = 120 - 90 = 30
More % $$ = \frac{{30}}{{90}} \times 100 = 33\frac{1}{3}\% $$
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$

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