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In an examination, B obtained 20%, more marks than those obtained by A, and A obtained 10% less marks than those obtained by C. D obtained 20% marks than those obtained by C. By what percentage are the marks obtained by D more than those obtained by A?

A. $$43\frac{1}{3}\% $$

B. $$23\frac{1}{3}\% $$

C. $$13\frac{1}{3}\% $$

D. $$33\frac{1}{3}\% $$

Answer: Option D

Solution (By Examveda Team)

Let C marks = 100
Percentage mcq question image
More = 120 - 90 = 30
More % $$ = \frac{{30}}{{90}} \times 100 = 33\frac{1}{3}\% $$

This Question Belongs to Arithmetic Ability >> Percentage

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