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In an institute, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 90, find the total number of students getting 50% concessions if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?

A. 360

B. 280

C. 320

D. 330

E. 350

Answer: Option D

Solution(By Examveda Team)

Let us assume there are 100 students in the institute.
Then, number of boys = 60
And, number of girls = 40
Further, 15% of boys get fee waiver = 9 boys
7.5% of girls get fee waiver = 3 girls
Total = 12 students who gets fee waiver
But, here given 90 students are getting fee waiver. So we compare
12 = 90
So, 1 = $$\frac{{90}}{{12}}$$ = 7.5
Now number of students who are not getting fee waiver = 51 boys and 37 girls
50% concession = 25.5 boys and 18.5 girls (i.e. total 44)
Hence, required students = 44 × 7.5 = 330

This Question Belongs to Arithmetic Ability >> Percentage

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Comments ( 2 )

  1. Shubham Singh
    Shubham Singh :
    6 years ago

    60%*15%+40%*7.5%=12%
    12%=90
    1=750
    750-90=660
    50%= 330

  2. Keerti Patwa
    Keerti Patwa :
    7 years ago

    let total students = x
    then
    (15/100*60/100*x)+(7.5/100*40/100*x)=90
    900x+300x=90,0000
    x=750
    number of students who are not getting fee waiver=750-90=660
    50% of those not getting a fee waiver are eligible=660/2=330
    required students=330

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