In an ionic crystal if the valancies of cation and anion are V_C and V_A and the coordination numbers of cation and anions are Nc and N_A respectively, then the necessary condition for obtaining a stable crystal structure is

A) $$\frac{{{V_C}}}{{{N_C}}} = \frac{{{V_A}}}{{{N_A}}}$$ B) V_C.V_A = N_C.N_A C) $$\frac{{{V_C}}}{{{N_A}}} = \frac{{{V_A}}}{{{N_C}}}$$ D) $$\frac{{{V_C}}}{{{V_A}}} = \frac{{\surd {N_C}}}{{\surd {N_A}}}$$

Answer & Solution

Correct Answer: Option D

Let's discuss the solution. Join the discussion

Question posted by Examveda

Community

Join the Discussion

Join the discussion

Login to post a comment or share your explanation.

No comments yet Be the first to discuss this question.

Keep Learning

In an ionic crystal if the valancies of cation and anion...

In an ionic crystal if the valancies of cation and anion are VC and VA and the coordination numbers of cation and anions are Nc and NA respectively, then the necessary condition for obtaining a stable crystal structure is

Join the Discussion

Related Questions on Physics of Metals in Metallurgy

In an ionic crystal if the valancies of cation and anion are V_C and V_A and the coordination numbers of cation and anions are Nc and N_A respectively, then the necessary condition for obtaining a stable crystal structure is