In circular measure, the value of the angle 11° 15' is?

$$\eqalign{ & {\text{1}}{{\text{1}}^ \circ }{\text{15'}} = {\text{1}}{{\text{1}} + }\frac{{{\text{15}}}}{{60}} = 11 + \frac{1}{4} = \frac{{{{45}^ \circ }}}{4} \cr & {\text{We know }}\pi {\text{ radian}} = {180^ \circ } \cr & {1^ \circ } = \left( {\frac{\pi }{{{{180}^ \circ }}}} \right){\text{radian,}} \cr & \frac{{{{45}^ \circ }}}{4} = \frac{\pi }{{{{180}^ \circ }}} \times \frac{{{{45}^ \circ }}}{4} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{{{\pi ^c}}}{{16}}{\text{ }} \cr} $$