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In considering friction of a V-thread, the virtual coefficient of friction (μ1) is given by

A. μ1 = μsinβ

B. μ1 = μcosβ

C. $${\mu _1} = \frac{\mu }{{\sin \beta }}$$

D. $${\mu _1} = \frac{\mu }{{\cos \beta }}$$

Answer: Option D

Solution (By Examveda Team)

The virtual coefficient of friction in a V-thread is derived from the normal reaction forces and frictional forces acting on the inclined plane of the thread.

In a V-thread, the friction force is influenced by the helix angle and the thread angle (\(\beta\)). The relationship between the actual coefficient of friction (\(\mu\)) and the virtual coefficient of friction (\(\mu_1\)) is determined by resolving forces along and perpendicular to the inclined thread surface.

For a V-thread, the normal force component acts at an angle, leading to the effective coefficient of friction being altered by a factor of \( \cos \beta \).

Thus, the virtual coefficient of friction is given by:

\[ \mu_1 = \frac{\mu}{\cos \beta} \]

This indicates that the effective friction increases as the thread angle (\(\beta\)) increases because the normal force component decreases, requiring a larger effective friction to compensate.

This Question Belongs to Mechanical Engineering >> Theory Of Machine

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Comments (8)

  1. JITESH KAWA
    JITESH KAWA:
    7 months ago

    Explain it

  2. K Ashok
    K Ashok:
    1 year ago

    Solution

  3. RITESH SHRIVASTAV
    RITESH SHRIVASTAV:
    4 years ago

    Ans is:- option(C) if the angle is 2×B of thread angle

  4. Kudrat Sharma
    Kudrat Sharma:
    6 years ago

    In V threads, the normal reaction acts at an angle beta which is the semi groove angle. This normal reaction is increased as its axial component must be equal to the load W acting in the horizontal direction.

    W = R cos beta
    or R = W/ cos beta.

    Friction F = nu R
    or F = (nu W) / cos beta
    or F = (nu / cos beta) W
    or F = nu' W

    where nu' is the virtual coefficient of friction.

  5. ER Manjeet
    ER Manjeet:
    6 years ago

    Please explain it proper

  6. Wakawa Harami
    Wakawa Harami:
    6 years ago

    More explanation please

  7. Durga Prasad
    Durga Prasad:
    6 years ago

    Explanation

  8. Pranay Sreeramoju
    Pranay Sreeramoju:
    6 years ago

    Can u explain for me

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