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This question belongs to Electronics And Communications Engineering Digital Communication

Digital Communication

?

In QPSK the average probability of bit error in AWGN channel is obtained as

A) $${P_{eQPSK}} = Q\left[ {\sqrt {\frac{{2{E_b}}}{{{N_o}}}} } \right]$$ B) $${P_{eQPSK}} = {Q^2}\left[ {\sqrt {\frac{{2{E_b}}}{{{N_o}}}} } \right]$$ C) $${P_{eQPSK}} = Q\left[ {\sqrt {\frac{{{E_b}}}{{{N_o}}}} } \right]$$ D) $${P_{eQPSK}} = Q\left[ {\frac{1}{2}\sqrt {\frac{{2{E_b}}}{{{N_o}}}} } \right]$$

Answer & Solution

Correct Answer: Option A

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