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In the neighborhood of z = 1 the function f(z) has...

This question belongs to Engineering Maths Complex Variable
Complex Variable
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In the neighborhood of z = 1, the function f(z) has a power series expansion of the form $${\text{f}}\left( {\text{z}} \right) = 1 + \left( {1 - {\text{z}}} \right) + {\left( {1 - {\text{z}}} \right)^2} + \,...$$
Then f(z) is

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Correct Answer: Option A
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