In the reaction shown below, X and Y respectively are \[M{n_2}{\left( {CO} \right)_{10}}\xrightarrow{{\,\,\,Na\,\,\,}}\left( X \right)\xrightarrow{{C{H_3}CoCl}}\left( Y \right)\]
A. [Mn(CO)4]2-, [CH3C(O)Mn(CO)5]-
B. [Mn(CO)5]-, [CH3C(O)Mn(CO)5]
C. [Mn(CO)5]-, [Cl(CO)5]
D. [Mn(CO)4]2-, [ClMn(CO)5]-
Answer: Option B
Related Questions on Transition Elements
A. Lu3+, Yb3+, Dy3+, Eu3+
B. Eu3+, Dy3+, Yb3+, Lu3+
C. Dy3+, Yb3+, Eu3+, Lu3+
D. Yb3+, Dy3+, Lu3+ , Eu3+
A. D4h and (C2v and C2h)
B. Td and (C2v and D4h)
C. D4h and (C2v and D4h)
D. Td and (C2v and C4v)
The complex that exists as a pair of enantiomers is
A. trans-[CO(H2NCH2CH2NH2)2Cl2]+
B. cis-[Co(NH3)4Cl2]+
C. [Pt(PPh3)(Cl)(Br)(CH3)]-
D. [Co(H2NCH2CH2NH2)3]3+
The complex formed in the brown ring test for nitrates is
A. [Fe(H2O)5NO]3+
B. [Fe(H2O)5NO]2+
C. [Fe(H2O)4(NO)]2+
D. [Fe(H2O)4(NO)]3+

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