Directions (1 - 4): A health-drink company's in R & D department is trying to make various diet formulation, which can be used for certain specific purpose. It is considering a choice of 5 alternative ingredients (O, P, Q, R and S), which can be used in different proportions in the formulations. The table below gives the composition of these ingredients. the cost per unit of each of these ingredients is as O: 150, P: 50, Q: 200, R: 500, S: 100.
In what proportion P, Q and S should be mixed to make a diet having least 60% carbohydrate at the lowest per unit cost?
A. 2 : 1 : 3
B. 4 : 1 : 2
C. 2 : 1 : 4
D. 3 : 1 : 2
E. 4 : 1 : 1
Answer: Option E
Solution(By Examveda Team)
To make diet with at lest 60% carbohydrate we can use option (B) and (E) only, but the lowest cost per unit can be given by when P, Q and S are mixed in the ratio 4 : 1 : 1This Question Belongs to Data Interpretation >> Table Chart
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Comments ( 2 )
Related Questions on Table Chart
Price of P = Rs 50,
Price of Q = Rs. 200.
Price of S = Rs. 100.
First condition = at least 60% Carbohydrates.
Second Condition = Lowest Cost.
If You take option 1.
2 unit, 1 unit and 3 unit. In this
% of Carbohydrate = (2/6) *100 = 33.33%. (Not qualify the first condition).
Similarly, Option 3 and for also will not qualify the first condition. You can do the calculation yourself. Then, we left with option 2 and 5 which may contain 60% carbohydrates. But, Option 2 also don't qualify condition 1.
4/7 = 5.7 = 57%.
Option 5.
Carbohydrate = 4/6 = 6.66 = 66.6%. So, option 5 is correct .
how this solution is solved?