A number is first decreased by 10% and then increased by 10%. The number so obtained is 50 less than the original number. The original number is :
A. 5000
B. 5050
C. 5500
D. 5900
Answer: Option A
Solution(By Examveda Team)
Let the original number be $$x$$Final number obtained :
= 110% of (90% of $$x$$)
= $$\left( {\frac{{110}}{{100}} \times \frac{{90}}{{100}} \times x} \right)$$
= $$\frac{{99x}}{{100}}$$
$$\eqalign{ & \therefore x - \frac{{99x}}{{100}} = 50 \cr & \Rightarrow \frac{x}{{100}} = 50 \cr & \Rightarrow x = 50 \times 100 \cr & \Rightarrow x = 5000 \cr} $$
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
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