LCM of two prime numbers x and y (x > y) is 161. Then the value of 3y - x is = ?

A. -2

B. -1

C. 1

D. 2

Answer: Option A

Solution(By Examveda Team)

HCF of two prime numbers is 1
Product of numbers = (1 × 161) = 161
Let the numbers be a and b.
Then, ab = 161
Now, co-primes with product 161 are (1, 161) and (7, 23)
Since x and y are prime numbers and x > y, we have x = 23 and y = 7
∴ 3y - x = (3 × 7) - 23 = - 2