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Let 0 < x < 1, then the correct inequality is = ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& 0 < x < 1, \cr
& {\text{Let }}x = \frac{4}{{10}} \cr
& {\text{So}},\sqrt x = \frac{2}{{\sqrt {10} }}\,\& \, \cr
& \,\,{x^2} = \frac{{16}}{{100}} = 0.16 \cr
& {\text{Now}}, \cr
& \because 0.16 < \frac{4}{{10}} < \frac{2}{{\sqrt {10} }} \cr
& \therefore {x^2} < x < \sqrt x \cr} $$
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