Let 0 < x < 1, then the correct inequality is = ?
A. $$x < \sqrt x < {x^2}$$
B. $$\sqrt x < x < {x^2}$$
C. $${x^2} < x < \sqrt x $$
D. $$\sqrt x < {x^2} < x$$
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & 0 < x < 1, \cr & {\text{Let }}x = \frac{4}{{10}} \cr & {\text{So}},\sqrt x = \frac{2}{{\sqrt {10} }}\,\& \, \cr & \,\,{x^2} = \frac{{16}}{{100}} = 0.16 \cr & {\text{Now}}, \cr & \because 0.16 < \frac{4}{{10}} < \frac{2}{{\sqrt {10} }} \cr & \therefore {x^2} < x < \sqrt x \cr} $$This Question Belongs to Arithmetic Ability >> Simplification
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