Let 0 < x < 1, then the correct inequality is = ?

A. $$x < \sqrt x < {x^2}$$  

B. $$\sqrt x < x < {x^2}$$  

C. $${x^2} < x < \sqrt x $$  

D. $$\sqrt x < {x^2} < x$$  

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & 0 < x < 1, \cr & {\text{Let }}x = \frac{4}{{10}} \cr & {\text{So}},\sqrt x = \frac{2}{{\sqrt {10} }}\,\& \, \cr & \,\,{x^2} = \frac{{16}}{{100}} = 0.16 \cr & {\text{Now}}, \cr & \because 0.16 < \frac{4}{{10}} < \frac{2}{{\sqrt {10} }} \cr & \therefore {x^2} < x < \sqrt x \cr} $$