Let a, b and c be the fractions such that a < b < c. If c is divided by a, the result is $$\frac{5}{2}$$, which exceeds b by $$\frac{7}{4}$$. If a + b + c = $$1\frac{{11}}{{12}}$$ , then (c - a) will be equal to:

Solution (By Examveda Team)

$$\eqalign{ & \frac{c}{a} = \frac{5}{2} \cr & b = \frac{5}{2} - \frac{7}{4} \cr & b = \frac{3}{4} \cr & a + b + c = \frac{{23}}{{12}} \cr & a + c = \frac{{23}}{{12}} - \frac{3}{4} \cr & a + c = \frac{{14}}{{12}} \cr & a + c = \frac{7}{6} \cr & 2x + 5x = \frac{7}{6}\,\,\,\,\,\,\left\{ {\frac{c}{a} = \frac{{5x}}{{2x}}} \right. \cr & 7x = \frac{7}{6} \cr & x = \frac{1}{6} \cr & c - a = 3x = 3 \times \frac{1}{6} = \frac{1}{2} \cr} $$