Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?
A. 4
B. 5
C. 6
D. 8
Answer: Option A
Solution(By Examveda Team)
N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4
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