Let the least number of six digits which when divided by 4, 6, 10, 15 leaves in each case same remainder 2 be N. The sum of digits in N is = ?

A. 3

B. 5

C. 4

D. 6

Answer: Option B

Solution(By Examveda Team)

LCM (4, 6, 10, 15)
LCM = 2 × 2 × 3 × 5 = 60
⇒ Least number of six digit = 100000
⇒ Divide 100000 by 60 we get remainder 40
⇒ Least six digit number which is divisible by (4, 6, 10, 15)given number is
[100000 + (60 - 40)] = 100020
∴ N ⇒ 100020 + 2 = 100022
∴ Sum of digits = 1 + 0 + 0 + 0 + 2 + 2 = 5