Let x be the least number which when divided by 15,18, 20 and 27, the remainder in each case is 10 and x is a multiple of 31. What least number should be added to x to make it a perfect square?
A. 39
B. 37
C. 43
D. 36
Answer: Option A
Solution (By Examveda Team)
L.C.M. of 15,18, 20, 27 = 540x = 540K + 10
x = 540 × 4 + 10 = 2170
462 < 2170 > 472
472 = 2209
To make perfect square = 2209 - 2170 = 39
This Question Belongs to Arithmetic Ability >> Number System
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