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Let y[n] denote the convolution of h[n] and g[n], where h[n] = $${\left( {\frac{1}{2}} \right)^n}$$ u[n] and g[n] is a causal sequence. If y[0] = 1 and y[1] = $$\frac{1}{2},$$ then g[1] equals

A. 0

B. $${1 \over 2}$$

C. 1

D. $${3 \over 2}$$

Answer: Option A


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