Let y[n] denote the convolution of h[n] and g[n], where h[n] = $${\left( {\frac{1}{2}} \right)^n}$$ u[n] and g[n] is a causal sequence. If y[0] = 1 and y[1] = $$\frac{1}{2},$$ then g[1] equals
A. 0
B. $${1 \over 2}$$
C. 1
D. $${3 \over 2}$$
Answer: Option A
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