Examveda

\[\mathop {\lim }\limits_{{\text{x}} \to 0} \frac{{{{\log }_{\text{e}}}\left( {1 + 4{\text{x}}} \right)}}{{{{\text{e}}^{3{\text{x}}}} - 1}}\]   is equal to

A. 0

B. \[\frac{1}{{12}}\]

C. \[\frac{4}{3}\]

D. 1

Answer: Option C


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