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Mitscherlich factor for phosphorus is

A. 0.301

B. 0.4

C. 1.22

D. 0.6

Answer: Option D

Solution(By Examveda Team)

The equation introduced by Mitscherlich has been generally used to express nutrient-yield relationships as follows: $${\bf{y = A}}\left( {{\bf{1 - }}{{\bf{e}}^{{\bf{ - eb - ex}}}}} \right).$$
The classical Mitscherlich equation is based on Leibig’s Law of the Minimum and describes the yield response of a crop to an increase in the main factor that is limiting growth.
Mitscherlich's factor for phosphorus is 0.6.

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