Mitscherlich factor for phosphorus is
A. 0.301
B. 0.4
C. 1.22
D. 0.6
Answer: Option D
Solution(By Examveda Team)
The equation introduced by Mitscherlich has been generally used to express nutrient-yield relationships as follows: $${\bf{y = A}}\left( {{\bf{1 - }}{{\bf{e}}^{{\bf{ - eb - ex}}}}} \right).$$The classical Mitscherlich equation is based on Leibig’s Law of the Minimum and describes the yield response of a crop to an increase in the main factor that is limiting growth.
Mitscherlich's factor for phosphorus is 0.6.
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