Answer & Solution
Answer: Option C
Solution:
Explanation:
Step 1:
The given IP address is 200.10.5.68 with a subnet mask of /28.
Step 2:
Convert the subnet mask from its decimal representation to binary.
The subnet mask /28 corresponds to 255.255.255.240 in decimal, which is 11111111.11111111.11111111.11110000 in binary.
Step 3:
Perform a bitwise "AND" operation between the IP address and the subnet mask.
IP address: 200.10.5.68 -> 11001000.00001010.00000101.01000100
Subnet mask: 255.255.255.240 -> 11111111.11111111.11111111.11110000
Subnet (AND): 200.10.5.64 -> 11001000.00001010.00000101.01000000
Step 4:
The result of the "AND" operation is the subnetwork address.
Therefore, the subnetwork address for the host with the IP address 200.10.5.68/28 is:
C. 200.10.5.64
This output corresponds to the subnetwork address obtained by applying the subnet mask to the given IP address.