Pipe A can fill the tank in 8 hours and pipe B can fill it in 12 hours. If pipe A is opened at 7:00 AM and pipe B is opened at 9:00 AM, then at what time will the tank be full ?
A. 12:00 PM
B. 12:30 PM
C. 11:48 PM
D. 12:36 PM
Answer: Option D
Solution(By Examveda Team)
A opened 2 hours early to B
In 2 hours A can do 3 × 2 = 6 unit work
Remaining work = 24 - 6 = 18
A + B can do it in
$$\eqalign{ & = \frac{{18}}{5}{\text{hours}} \cr & = 3\frac{3}{5}{\text{hours}} \cr & {\text{ = 3}}\,{\text{hours 36 minutes}} \cr} $$
∴ Tank will be full in 9 AM + 3 hours 36 minutes = 12.36 PM
Related Questions on Pipes and Cistern
A. $$\frac{5}{{11}}$$
B. $$\frac{6}{{11}}$$
C. $$\frac{7}{{11}}$$
D. $$\frac{8}{{11}}$$
A. $$1\frac{{13}}{{17}}$$ hours
B. $$2\frac{8}{{11}}$$ hours
C. $$3\frac{9}{{17}}$$ hours
D. $$4\frac{1}{2}$$ hours
A. $$4\frac{1}{3}$$ hours
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C. 8 hours
D. 14 hours
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