Pipes A and B can fill a tank in 16 hours and 24 hours, respectively, whereas pipe C and empty the full tank is 40 hours. All three pipes are opened together, but pipe C is closed after 10 hours. After how many hours will the remaining part of the tank be filled?
A. 2
B. $$2\frac{1}{2}$$
C. 5
D. $$5\frac{1}{2}$$
Answer: Option A
Solution (By Examveda Team)
All three pipe opened together in 10 hours = (15 + 10 - 6) × 10 = 190
Remaining work = 240 - 190 = 50
Remaining work done by A and B $$ = \frac{{50}}{{15 + 10}} = 2$$
This Question Belongs to Arithmetic Ability >> Pipes And Cistern
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