Population of a town increase 2.5% annually but is decreased by 0.5% every year due to migration. What will be the percentage increase in 2 years?
A. 5%
B. 4.04%
C. 4%
D. 3.96%
Answer: Option B
Solution(By Examveda Team)
Net percentage increase in Population = (2.5 - 0.5) = 2% each year. Let the Original Population of the town be 100. Population of Town after 1 year = (100 + 2% of 100) = 102. Population of the town after 2nd year = (102 + 2% of 102 ) = 104.04Now, % increase in population = $$\frac{{4.04}}{{100}} \times 100 = 4.04\% $$ Mind Calculation Method: 100 == 2% Up(1st year) ==> 102 == 2%Up(2nd year) ==> 104.04 % population increase in 2 years = 4.04%.
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Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
There is 2% increase in population by 2.5-0.5
By applying this formula we can get a desired result : -
(a + b) + ab / 100 here for a and b the value will be same as 2
(2+2) + 2*2 / 100 = 4.04
easy increase in 2 year 2.5%+2.5%=5%
now decrease in 2 year 0.5+0.5%=1
now 5-1%=4
easy increase in 2 year 2.5%+2.5%=5%
now decrease in 2 year 0.5+0.5%=1
now 5-1%=4
The population of a city was 50000; In the first 2 years it grew an annual increase of 5% in the next 3 years it grew an annual increase of 20% and in the last year due to epidemic there is an annual decrease of 10%, what was its population after years .
From where 4.04 come?? How?
See, the net change in the population is 25 which is coming from,
2.5 - 0.5 = 2.
if you are doing mind calculation then this little calculation would be understandable. Think think you understand it.
actually admin i got it..was little confused..
plz explain that in mind calculating method..there is no need of the value 2.5 and 0.5