Power required (in watts) to drive a centrifugal pump is (where Hm = Manometric head in metres, w = Specific weight in N/m3, Q = Discharge of the pump in m3/s and $${\eta _{\text{o}}}$$ = Overall efficiency of the pump)
A. $$\frac{{{\text{w}}{{\text{H}}_{\text{m}}}}}{{{\text{Q}} \times {\eta _{\text{o}}}}}$$
B. $$\frac{{{\text{wQ}}{{\text{H}}_{\text{m}}}}}{{{\eta _{\text{o}}}}}$$
C. $$\frac{{{\text{wQ}}}}{{{{\text{H}}_{\text{m}}} \times {\eta _{\text{o}}}}}$$
D. $$\frac{{{\text{wQ}} \times {\eta _{\text{o}}}}}{{{{\text{H}}_{\text{m}}}}}$$
Answer: Option B
This Question Belongs to Mechanical Engineering >> Hydraulics And Fluid Mechanics In ME
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