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Pressure of water vapour is given by
Answer & Solution
Correct Answer:
Option
D
Pressure of water vapour is given by, $$ln\left( {\frac{{{{\text{P}}_1}}}{{{{\text{P}}_2}}}} \right) = \left( {\frac{{\Delta {\text{Hvap}}}}{{\text{R}}}} \right)\left( {\frac{1}{{{{\text{T}}_2}}} - \frac{1}{{{{\text{T}}_1}}}} \right)$$
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