Examveda

Recycling back of outlet stream to the reactor from an ideal CSTR carrying out a first order liquid phase reaction will result in __________ in conversion.

A. Decrease

B. Increase

C. No change

D. Either A or B, depends on the type of reaction

Answer: Option C


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Comments (1)

  1. Atanu Chatterjee
    Atanu Chatterjee:
    4 months ago

    The correct answer is:
    B. Increase

    🔍 Explanation:
    In an ideal Continuous Stirred Tank Reactor (CSTR) conducting a first-order liquid-phase reaction, recycling a portion of the reactor outlet back to the inlet will:

    Increase the reactant residence time in the system.

    Expose unconverted reactants to the catalyst/reactive zone multiple times, effectively enhancing conversion.

    Make the system behave more like a plug flow reactor (PFR) as the recycle ratio increases — and a PFR gives higher conversion than a CSTR for first-order reactions at the same space time.

    💡 Why conversion increases:
    In a single CSTR, due to perfect mixing, reactants are immediately diluted with products — leading to lower conversion.

    With recycle, the fresh feed is diluted with unconverted reactants, which improves conversion efficiency across the system.

    ✅ Final Answer:
    B. Increase

Related Questions on Chemical Reaction Engineering

A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and $${{\text{k}}_{\text{g}}}$$ respectively. The effective rate constant (keff) is given by

A. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\text{k}} + {{\text{k}}_{\text{g}}}$$

B. $${{\text{k}}_{\text{e}}}{\text{ff}} = \frac{{{\text{k}} + {{\text{k}}_{\text{g}}}}}{2}$$

C. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\left( {{\text{k}}{{\text{k}}_{\text{g}}}} \right)^{\frac{1}{2}}}$$

D. $$\frac{1}{{{{\text{k}}_{\text{e}}}{\text{ff}}}} = \frac{1}{{\text{k}}} + \frac{1}{{{{\text{k}}_{\text{g}}}}}$$