$$\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}$$    is equal to = ?

Solution(By Examveda Team)

$$\eqalign{ & {\text{According to question,}} \cr & \Rightarrow \frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}\,\,\,\,\,\,\, \cr & \,\,\,\,\,\,\,\,\,\,\,\left[ {\therefore {a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)} \right] \cr & \Rightarrow \frac{{\left( {7.5 + 1} \right)\left[ {{{\left( {7.5} \right)}^2} + 1 - 7.5 \times 1} \right]}}{{{{\left( {7.5} \right)}^2} - 7.5 \times 1 + {1^2}}} \cr & \Rightarrow 8.5 \cr} $$