If $$\sqrt 3 {\text{ = 1}}{\text{.7321,}}$$   then the value of $$\sqrt {192} - \frac{1}{2}\sqrt {48} - \sqrt {75} {\text{,}}$$     correct to 3 place of decimal, is = ?

A. 8.661

B. 4.331

C. 1.732

D. -1.732

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{According to question,}} \cr & \sqrt {192} - \frac{1}{2}\sqrt {48} - \sqrt {75} \cr & \Rightarrow 8\sqrt 3 - \frac{4}{2}\sqrt 3 - 5\sqrt 3 \cr & \Rightarrow 8\sqrt 3 - 2\sqrt 3 - 5\sqrt 3 \cr & \Rightarrow \sqrt 3 \cr & \Rightarrow 1.732 \cr} $$