The value of $$\sqrt {32} $$  - $$\sqrt {128} $$  + $$\sqrt {50} $$ correct to 3 places of decimal is $$\sqrt {32} $$  - $$\sqrt {128} $$  + $$\sqrt {50} $$  = ?

Solution (By Examveda Team)

$$\eqalign{ & {\text{According to question,}} \cr & \sqrt {32} {\text{ }} - \sqrt {128} {\text{ + }}\sqrt {50} \cr & \Rightarrow \sqrt {16 \times 2} - \sqrt {64 \times 2} + \sqrt {25 \times 2} \cr & \Rightarrow 4\sqrt 2 - 8\sqrt 2 + 5\sqrt 2 \cr & \Rightarrow \sqrt 2 \cr & \Rightarrow 1.414 \cr} $$