The value of $$\sqrt {32} $$ - $$\sqrt {128} $$ + $$\sqrt {50} $$ correct to 3 places of decimal is $$\sqrt {32} $$ - $$\sqrt {128} $$ + $$\sqrt {50} $$ = ?
A. 1.732
B. 1.141
C. 1.414
D. 1.441
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{According to question,}} \cr & \sqrt {32} {\text{ }} - \sqrt {128} {\text{ + }}\sqrt {50} \cr & \Rightarrow \sqrt {16 \times 2} - \sqrt {64 \times 2} + \sqrt {25 \times 2} \cr & \Rightarrow 4\sqrt 2 - 8\sqrt 2 + 5\sqrt 2 \cr & \Rightarrow \sqrt 2 \cr & \Rightarrow 1.414 \cr} $$Related Questions on Simplification
A. 20
B. 80
C. 100
D. 200
E. None of these
A. Rs. 3500
B. Rs. 3750
C. Rs. 3840
D. Rs. 3900
E. None of these
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