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sin4θ + cos4θ in terms of sinθ can be written as:
Answer & Solution
Correct Answer:
Option
D
(sin2θ + cos2θ)2 = 1
sin4θ + cos4θ + 2sin2θ.cos2θ = 1
sin4θ + cos4θ = 1 - 2sin2θ.cos2θ
sin4θ + cos4θ = 1 - 2sin2θ(1 - sin2θ)
sin4θ + cos4θ = 1 - 2sin2θ + 2sin4θ
sin4θ + cos4θ + 2sin2θ.cos2θ = 1
sin4θ + cos4θ = 1 - 2sin2θ.cos2θ
sin4θ + cos4θ = 1 - 2sin2θ(1 - sin2θ)
sin4θ + cos4θ = 1 - 2sin2θ + 2sin4θ
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