Solution of the differential equation \[x\frac{{dy}}{{dx}} + y = {x^4},\] with the boundary condition that y = 1, at x = 1, is
A. \[y = 5{x^4} - 4\]
B. \[y = \frac{{{x^4}}}{5} + \frac{{4x}}{5}\]
C. \[y = \frac{{4{x^4}}}{5} + \frac{1}{{5x}}\]
D. \[y = \frac{{{x^4}}}{5} + \frac{4}{{5x}}\]
Answer: Option D


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