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Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms. $${\text{5}}\frac{1}{x} \times y\frac{3}{4} = 20$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& {\text{Given equation is :}} \cr
& \frac{{\left( {5x + 1} \right)}}{x} \times \frac{{\left( {4y + 3} \right)}}{4} = 20 \cr
& \Leftrightarrow \left( {5x + 1} \right)\left( {4y + 3} \right) = 80x \cr
& {\text{Clearly, }}x = 3{\text{ and}} \cr
& {\text{ }}y = 3{\text{ satisfy}} \cr} $$
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