Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms. $${\text{5}}\frac{1}{x} \times y\frac{3}{4} = 20$$

Solution (By Examveda Team)

$$\eqalign{ & {\text{Given equation is :}} \cr & \frac{{\left( {5x + 1} \right)}}{x} \times \frac{{\left( {4y + 3} \right)}}{4} = 20 \cr & \Leftrightarrow \left( {5x + 1} \right)\left( {4y + 3} \right) = 80x \cr & {\text{Clearly, }}x = 3{\text{ and}} \cr & {\text{ }}y = 3{\text{ satisfy}} \cr} $$