Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. 8 years ago, what was the ratio of Tanya's age to that of her grandfather ?
A. 1 : 2
B. 1 : 5
C. 3 : 8
D. None of these
Answer: Option D
Solution(By Examveda Team)
16 years ago, let T = x years and G = 8x yearsAfter 8 years from now,
T = (x + 16 + 8) years and G = (8x + 16 + 8) years
$$\eqalign{ & \therefore {\text{8x + 24 = 3}}\left( {x + 24} \right) \cr & \Rightarrow 8x - 3x = 72 - 24 \cr & \Rightarrow 5x = 48 \cr & 8{\text{years ago,}} \cr & {\text{ }}\frac{{\text{T}}}{{\text{G}}} \cr & = \frac{{x + 8}}{{8x + 8}} \cr & = \frac{{\frac{{48}}{5} + 8}}{{8 \times \frac{{48}}{5} + 8}} \cr & = \frac{{48 + 40}}{{384 + 40}} \cr & = \frac{{88}}{{424}} \cr & = \frac{{11}}{{53}} \cr} $$
Related Questions on Problems on Ages
A. 2 times
B. $$2\frac{1}{2}\,{\text{times}}$$
C. $$2\frac{3}{4}\,{\text{times}}$$
D. 3 times
A. 4 years
B. 8 years
C. 10 years
D. None of these
A. 14 years
B. 19 years
C. 33 years
D. 38 years
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