The average of 25 numbers is 64. The average of the first 13 numbers and that of the last 13 numbers are 62.8 and 72.2, respectively. If the 12th number is 61, and if the 12th and 13th numbers are excluded, then what is the average of the remaining number (correct to one decimal place)?
A. 59.2
B. 61.5
C. 60.2
D. 62.2
Answer: Option C
Solution(By Examveda Team)
Average of 25 numbers = 64Sum of 25 numbers = 64 × 25 = 1600
Average of first 13 numbers = 62.8
Sum of first 13 numbers = 62.8 × 13 = 816.4
Average of last 13 numbers = 72.2
Sum of last 13 numbers = 72.2 × 13 = 938.6
13th number = 816.4 + 938.4 - 1600
= 1754.8 - 1600
= 154.8
12th number = 61
If we remove 12th and 13th number then, sum of remaining numbers = 1600 - 61 - 154.8 = 1384.2
Average $$ = \frac{{1384.2}}{{23}} = 60.18 \sim 60.2$$
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