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The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. The average of the remaining two numbers is :
Answer & Solution
Correct Answer:
Option
A
Let the six number be a, b, c, d, e, f
According to the question,
⇒ $$\frac{a + b + c + d + e + f}{6}$$ = 3.95
⇒ a + b + c + d + e + f = 23.7.....(i)
$$\frac{a + b}{2}$$ = 3.4
⇒ a + b = 6.8.....(ii)
$$\frac{c + d}{2}$$ = 3.85
⇒ c + d = 7.7.....(iii)
Put the value of equation (ii) and equation (iii) in equation (i)
e + f = 23.7 - 7.7 - 6.8
e + f = 9.2
∴ Average =$$\frac{9.2}{2}$$ = 4.6
According to the question,
⇒ $$\frac{a + b + c + d + e + f}{6}$$ = 3.95
⇒ a + b + c + d + e + f = 23.7.....(i)
$$\frac{a + b}{2}$$ = 3.4
⇒ a + b = 6.8.....(ii)
$$\frac{c + d}{2}$$ = 3.85
⇒ c + d = 7.7.....(iii)
Put the value of equation (ii) and equation (iii) in equation (i)
e + f = 23.7 - 7.7 - 6.8
e + f = 9.2
∴ Average =$$\frac{9.2}{2}$$ = 4.6
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