?
The average of the first 100 positive integers is -
Answer & Solution
Correct Answer:
Option
C
According to the question,
As we know that average of 'n' positive integer is
= $$\frac{n(n + 1)}{2 × n}$$
= $$\frac{(n + 1)}{2}$$
Here n = 100
∴ $$\frac{100 + 1}{2}$$
= $$\frac{101}{2}$$
= 50.5
As we know that average of 'n' positive integer is
= $$\frac{n(n + 1)}{2 × n}$$
= $$\frac{(n + 1)}{2}$$
Here n = 100
∴ $$\frac{100 + 1}{2}$$
= $$\frac{101}{2}$$
= 50.5
Join the Discussion
Login to post a comment or share your explanation.
Login