The average of the largest and smallest 3 digits numbers formed by 0, 2 and 4 would be :

A. 312

B. 222

C. 213

D. 303

Answer: Option A

Solution(By Examveda Team)

According to the question,
Largest number = 420
Smallest number = 204
Average
= $$\frac{420 + 204}{2}$$
= $$\frac{624}{2}$$
= 312