The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:

Solution (By Examveda Team)

$$\eqalign{ & \frac{{a + b + c}}{3} = c + 2 \cr & a + b + c = 3c + 6 \cr & a + b = 2c + 6 \to \left( {\text{i}} \right) \cr & \frac{{a + b}}{2} = 48 \cr & a + b = 96 \cr & {\text{From equation }}\left( {\text{i}} \right) \cr & 96 = 2c + 6 \cr & c = 45 \cr & d = 35 \cr & {\text{The average of }}\left( {c + d} \right) \cr & = \frac{{45 + 35}}{2} \cr & = 40 \cr} $$