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The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?

A. Rs. 5, Rs.7.50

B. Rs. 8, Rs. 12

C. Rs. 16, Rs. 10

D. Rs. 12, Rs. 14

Answer: Option C

Solution(By Examveda Team)

Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
$$\left( {\frac{{160}}{{100}}} \right)x + y = 26$$
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.

This Question Belongs to Arithmetic Ability >> Average

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Comments ( 2 )

  1. Abduselam Isak
    Abduselam Isak :
    4 months ago

    Total cost of 10 books = Rs. 120
    Total cost of 8 books = Rs. 94
    ⇒ The cost of 2 books = Rs. 26
    Let the price of each book be x and y.
    ⇒ x + y = 26 - - - - - - (1)
    (160/100)x+y=26
    1.6x+x+y=26
    2.6x+y=26
    Y=26/2.6=10
    Y=10
    Now, Substituting y = 10 in (1) we get,
    x + 10 = 26
    X+10=26
    X=26-10=16
    x = 16
    So the price of each book is Rs. 16 and Rs. 10 respectively.

  2. Rahul Nath
    Rahul Nath :
    5 years ago

    without doing math it can be answered easily. -2+(16-12=+4)+(12-10=-2)=0

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