The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
A. Rs. 5, Rs.7.50
B. Rs. 8, Rs. 12
C. Rs. 16, Rs. 10
D. Rs. 12, Rs. 14
Answer: Option C
Solution(By Examveda Team)
Total cost of 10 books = Rs. 120Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
$$\left( {\frac{{160}}{{100}}} \right)x + y = 26$$
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
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Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
(160/100)x+y=26
1.6x+x+y=26
2.6x+y=26
Y=26/2.6=10
Y=10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
X+10=26
X=26-10=16
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
without doing math it can be answered easily. -2+(16-12=+4)+(12-10=-2)=0