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The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
Answer & Solution
Correct Answer:
Option
C
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
$$\left( {\frac{{160}}{{100}}} \right)x + y = 26$$
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
$$\left( {\frac{{160}}{{100}}} \right)x + y = 26$$
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
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LoginTotal cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
(160/100)x+y=26
1.6x+x+y=26
2.6x+y=26
Y=26/2.6=10
Y=10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
X+10=26
X=26-10=16
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.