?
The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
Answer & Solution
Correct Answer:
Option
D
Let the highest score be x
Then, lowest score = (x - 172)
Then,
⇔ (50 × 40) - [x + (x - 172)] = 38 × 48
⇔ 2x = 2000 + 172 - 1824
⇔ 2x = 348
⇔ x = 174
Then, lowest score = (x - 172)
Then,
⇔ (50 × 40) - [x + (x - 172)] = 38 × 48
⇔ 2x = 2000 + 172 - 1824
⇔ 2x = 348
⇔ x = 174
Join the Discussion
Login to post a comment or share your explanation.
Login