The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is

A. 165 runs

B. 170 runs

C. 165 runs

D. 174 runs

Answer: Option D

Solution(By Examveda Team)

Let the highest score be x
Then, lowest score = (x - 172)
Then,
⇔ (50 × 40) - [x + (x - 172)] = 38 × 48
⇔ 2x = 2000 + 172 - 1824
⇔ 2x = 348
⇔ x = 174